When a buffer has a higher concentration of the acid of the conjugate pair than the conjugate base, for the system to be at equilibrium (for
K to equal
Ka):
[H
3O
+] must be higher than
Ka.
because | Ka = [H3O+] × | [conjugate base] |
| [acid] |
Thus pH must be lower than p
Ka.
Making connections to remember this:
For any solution pH is lower if the concentration of the acid is higher.
For a buffer solution pH is lower than pKa if the concentration of acid is higher.
Provided the concentration of the acid is no more than ten times the concentration of the conjugate base, the pH will be within 1 unit of p
Ka.
Ka = [H
3O
+] × 10
–1 Take negative logarithm of all termsp
Ka = pH + 1
pH = p
Ka –1
See the graph which shows pH change on addition of NaOH to CH
3CO
2H (p
Ka 4.76). At 2.5
added NaOH the ratio of [conjugate base] to [acid] is 0.1, and the pH is 3.78.
titration curve ethanoic acid with sodium hydroxide | CH3CO2– |
CH3CO2H/ CH3CO2– |
CH3CO2H |
Buffers where the ratio [conjugate base] to [acid] is between 0.1 and 1 have pH between p
Ka –1 and p
Ka.