H2O can act as both an
acid and a
base, and the
proton transfer reaction shown below occurs to a
very small extent in pure water.
The equilibrium constant for the reaction is referred to as
Kw and has the value shown below at 25 °C.
H
2O(l) + H-OH(l)

H
3O
+(aq) +
–OH(aq)
Kw = [H
3O
+][OH
–]
At 25 °C
Kw = 10
–14 pKw = -log Kw
pKw = 14 at 25 °C
Like all equilibrium constants, the magnitude of
Kw depends on temperature.
The magnitude of
Kw at all temperatures is small, and it is convenient to use p
Kw which is defined similarly to pH.
| Useful maths: |
| 10a × 10b = 10a+b |
| 10a ÷ 10b = 10a-b |
pOH can be analogously defined (-log [OH
–]).
The relationship below follows from the rules for combining exponents that are given.
pKw = pH + pOH
If any two of these variables in this relationship are known, the third can be calculated.