Intermediates

If the slow step is second, the predicted rate law will usually involve an intermediate.
 
Possible mechanism
For reaction A + B C

Step 1: fast equilibrium
A + B intermediate

Step 2: slow
intermediate C

Predicted overall rate law
rate = k[intermediate]

It is not possible to test this rate law by varying [intermediate] because the intermediate is consumed as soon as it is formed, and is thus never present in significant concentration.

To test such a pathway, [intermediate] must be expressed in terms of concentrations of stable species (reactants and/or products).This can be done using the equilibrium constant (K) for the step forming the intermediate.
 
K=  [intermediate]
[A][B]

[intermediate] = K[A][B]

Substitution of the expression for the concentration of the intermediate into the predicted rate law above gives a rate law that can be experimentally verified.

rate = k × K[A][B]

The predicted rate constant for the overall reaction of A and B to give C would be the product of the rate constant (k - lower case) for the second step and the equilibrium constant (K - upper case) for the first step.