For the reaction: NH
4+(aq) + NO
2–(aq)

N
2(g) + 2H
2O(l)
Use the experimental data below to determine the rate law and
k, the rate constant.
| Experiment | Initial [NH4+] | Initial [NO2-] | Initial rate |
| 1 | 0.100 | 0.005 | 1.35 x l0-7 s-1 |
| 2 | 0.100 | 0.010 | 2.70 × 10-7 s-1 |
| 3 | 0.200 | 0.010 | 5.40 × 10-7 s-1 |
The general form of the rate law (equation) has the rate constant
k multiplied by concentrations of reactants.
The exponents on the concentration of reactants are experimentally determined.
For this reaction, the rate law is of the form: rate = k[NH
4+]
x[NO
2-]
y.
x and y are determined by how the rate changes if concentrations change:As doubling [NH4+] keeping [NO2–] constant doubles the initial rate, x = 1.
As doubling [NO2-] keeping [NH4+] constant doubles the initial rate, y = 1.
Therefore: rate = k[NH4+][NO2– ]
Calculate k by substituting data for one experiment:
k x 0.100
x 0.005
= 1.35 × l0
-7 s
-1k = 2.7 × 10
-4 s
-1 (Note the units depend on x and y.)