This same procedure can be used for other oxoanions where the central atom is from row 2 of the periodic tablle.
These elements can be surrounded by a maximum of four electron pairs.
First: Determine total number of available valence electrons. | ||
![]() | Group 14 C(4 × 1) | 4 |
| 2O Group 16 (6 × 2) | 12 | |
| H (1) | 1 | |
| Adjust for charge | 1 | |
| valence electrons available | 18 | |
Second: Subtract electrons used in bonds and as non-bonding pairs at outer atoms. | ||
| electrons used in bonds: electrons used to complete octets: electrons remaining: | –6 –12 0 | |
Third: When all electrons are accounted for, check for octet at central atom. | ||
![]() | Electrons at central atom: Electrons needed to complete octet | 6 2 |
Fourth: Complete octet at central atom by moving nonbonding electron pair(s) from oxygen to between central atom and O as bonds | ||
![]() to give final structure ![]() | ||
| Fifth: Deduce the shape of the ion after counting the number of electron pair domains at the central atom. | ||
| Number of bonding (single or double) domains plus the number of non-bonding electron pair domains. | Electron pair domains at C: | 3 |
| Position of outer atoms when the electron pair domains are as far apart as possible. | Shape of HCO2– | trigonal planar |