Preparation of alcohols from alkenes 1

Alcohols can be prepared from alkenes by addition of concentrated sulfuric acid across the double bond followed by reaction of the intermediate sulfate with water.  

The overall result is addition of H–OH across the double bond.
The H and the OH become bonded to carbons of the alkene that were doubly-bonded. 
There is no change in the arrangement of carbons. 
1. conc H2SO4

2. H2O

A single alcohol is produced above because the alkene is symmetrical
Symmetrical alkenes have the same groups attached to both of the doubly-bonded carbons.
 
In hex-3-ene above each of the doubly-bonded carbons is bonded to an H and a CH2CH3 group.
The alcohol produced is secondary because there are two carbons bonded to the carbon bearing OH.

This reaction may give rise to two products for unsymmetrical alkenes that have different groups at the two carbons of the double bond. 
 
The major product is the more substituted alcohol (the one with the larger number of carbons bonded to the carbon bearing OH).
Therefore secondary* and tertiary* alcohols can be prepared in good yield, but not primary* alcohols.
This guideline that can be used to predict the major product of the reaction is also known as Markownikoff's Rule.

1. conc H2SO4

2. H2O

major product
+

major product
+
minor product

*Tertiary alcohols have three carbons bonded to the carbon bearing OH. 
Secondary alcohols have two carbons bonded to the carbon bearing OH. 
Primary alcohols have one carbon bonded to the carbon bearing OH.