Reactions and preparation of haloalkanes

Classifying organic reactions by type highlights similarities between reactions that may at first appear different, and makes learning reaction chemistry easier. 

Preparation of haloalkanes from alkenes and alcohols
The most useful preparations  are those that result in introduction of halogen at specific carbon atoms with no change at other carbons.  Examples of these are the addition (In addition reactions of organic substrates the two reactants combine to give a single product with no atoms left over.) and substitution reactions (A substitution reaction of an organic molecule is one in which a part of the organic molecule is changed for a part of the reagent. Two products result (RH + Cl–Cl → RCl + HCl). ) given below.
 
addition
Alkenes react with halogen (X2) or HX at multiply bonded carbons.

CH2=CH2  +  Br–Br    BrCH2–CH2Br
CH2=CH2  +  H–Cl    HCH2–CH2Cl
 
substitution
Alcohols react with a variety of halogen-containing reagents to substitute the OH for halogen. Common ones are SOCl2, PCl3 (PBr3), PCl5, conc HCl (HBr).  The changes in the organic compound involved are shown below.  Additional products formed depend on the reagent used.


CH3CH2OH CH3CH2Cl
CH3CH2OH  CH3CH2Br

Reactions of haloalkanes to give alkenes, alcohols or amines.
Note that the reaction of haloalkanes to give alkenes is the reverse of the reaction above as is their substitution reaction to form alcohols.
 
elimination
Haloalkanes react with bases (commonly KOH or NaOH) to form alkenes.
In order for elimination to occur the carbon adjacent to the carbon bearing halogen must bear H.

HO + HCH2–CH2Cl HOH + CH2=CH2 + Cl
substitution 
Haloalkanes react with HO to give alcohols or with a larger excess of NH3 to give amines.
 
 CH3CH2Cl + OH   CH3CH2OH + Cl
CH3CH2Cl + NH3  CH3CH2NH2 + HCl

The HCl produced reacts with excess NH3 to give the ethylammonium chloride (NH4Cl).