| Ka = | [NH3][H3O+] |
| [NH4+] |
NH3 + H3O+Calculating the pH:
pKa and pH are related through the Ka expression
pKa and pH are related through the Ka expression
and
the reaction occurring to reach equililbrium. Enter formulae in these three spaces.
| 5.75 × 10–10 = | [H3O+][H3O+] |
| 0.05 |
[H3O+] = 5.36 × 10–6
pH = 5.27
Substituting from above into Ka expression:
Enter numbers at the left of the = (2 dp).
Enter an ion formula in the numerator.
Enter a number in the denominator.
Enter an ion formula in the numerator.
Enter a number in the denominator.
Note that the pH of the solution is less than 7, as would be expected for a solution in which the concentration of the acid of the pair is much higher than the concentration of the base of the pair. The pH is also less than pKa for the conjugate pair.